Problem 29 Find an equation for each line. ... [FREE SOLUTION] (2024)

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Chapter 2: Problem 29

Find an equation for each line. Write your final answer in slope–interceptform. Perpendicular to \(x+y=18 ; y\) -intercept \((0,-32)\)

Short Answer

Expert verified

The equation is \(y = x - 32\).

Step by step solution

02

Convert to slope-intercept form

Subtract \(x\) from both sides: \(y = -x + 18\). Thus, the slope (m) of this line is \(-1\).

03

Find the slope of the perpendicular line

The slope of any line perpendicular to another is the negative reciprocal of the original line's slope. Therefore, the slope of the perpendicular line is the negative reciprocal of \(-1\), which is \(1\).

04

Use the given y-intercept

The given y-intercept is \((0, -32)\). This means that when \(x = 0\), \(y = -32\). Therefore, the equation will take the form: \(y = mx + b\), where \(m = 1\) and \(b = -32\).

05

Write the final equation

Substitute the slope (m) and y-intercept (b) values into the slope-intercept form (y = mx + b): \(y = 1x - 32\). Thus, the equation of the line perpendicular to \(x + y = 18\) with a y-intercept of \((0, -32)\) is \(y = x - 32\).

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope-Intercept Form

The slope-intercept form is one of the most commonly used ways to express the equation of a straight line. It’s written as:
\[y = mx + b\]
In this form, **y** represents the y-coordinate, **x** represents the x-coordinate, **m** is the slope of the line, and **b** is the y-intercept. The slope **m** indicates how steep the line is. The y-intercept **b** indicates where the line crosses the y-axis.
To convert any linear equation into slope-intercept form, rearrange the equation to solve for **y**. For example, if you start with an equation like **x + y = 18**, you would subtract **x** from both sides to get: \[y = -x + 18\]This shows the line in slope-intercept form, where **m = -1** and **b = 18**.

Negative Reciprocal Slope

To understand lines that are perpendicular to each other, it's essential to grasp the concept of a negative reciprocal slope. Simply put, if two lines are perpendicular, the slope of one line is the negative reciprocal of the slope of the other line.
To find the negative reciprocal of a number:

  • First, take the reciprocal (flip the fraction). For instance, the reciprocal of 2 is 1/2.
  • Next, change the sign. If your original slope was positive, the negative reciprocal will be negative, and vice versa.

For example, if the slope of the given line is **-1** (as in the initial problem: **x + y = 18** converted to **y = -x + 18**), the slope of a line perpendicular to this would be **1** because the negative reciprocal of **-1** is **1**.

Y-Intercept

The y-intercept is the point where a line crosses the y-axis. This is an important characteristic because it shows the value of **y** when **x = 0**. In the slope-intercept form of a line (\[y = mx + b\]), **b** represents the y-intercept.
For instance, in the problem solution, the y-intercept is given as \[ (0, -32)\]. This means that the line crosses the y-axis at -32. To put it into the equation format, once we know the slope (which we found to be **1** as it’s perpendicular to **-1**), we can plug in the slope and y-intercept to get: \[y = 1x - 32\]With this, we have the equation of the line that is perpendicular to **x + y = 18** and has a y-intercept of **(0, -32)**.

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Problem 29 Find an equation for each line. ... [FREE SOLUTION] (3)

Most popular questions from this chapter

Let \(\left(x_{1}, y_{1}\right)\) and \(\left(x_{2}, y_{2}\right)\) be twodistinct points on the graph of \(y=m x+b .\) Use the fact that both pairs aresolutions of the equation to prove that \(m\) is the slope of the line given by\(y=m x+b\) (Hint: Use the slope formula.)Combine like terms. [ 1.3] Solve for \(m: x=\frac{m p}{c}\).If \((2,-3)\) and \((-5,4)\) are the endpoints of a diagonal of a square, what arethe coordinates of the other two vertices? What is the area of the square?Graph equation after plotting at least 10 points. \(y=\sqrt{x}+1 ;\) use \(x\) -values from 0 to 10Find \(k\) so that the graph of \(7 y-k x=9\) and the line containing the points\((2,-1)\) and \((-4,5)\) are perpendicular.
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Problem 29 Find an equation for each line. ... [FREE SOLUTION] (2024)

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